3.2.100 \(\int \frac {x}{(a+b x)^4} \, dx\)

Optimal. Leaf size=30 \[ \frac {a}{3 b^2 (a+b x)^3}-\frac {1}{2 b^2 (a+b x)^2} \]

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Rubi [A]  time = 0.01, antiderivative size = 30, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {43} \begin {gather*} \frac {a}{3 b^2 (a+b x)^3}-\frac {1}{2 b^2 (a+b x)^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x/(a + b*x)^4,x]

[Out]

a/(3*b^2*(a + b*x)^3) - 1/(2*b^2*(a + b*x)^2)

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin {align*} \int \frac {x}{(a+b x)^4} \, dx &=\int \left (-\frac {a}{b (a+b x)^4}+\frac {1}{b (a+b x)^3}\right ) \, dx\\ &=\frac {a}{3 b^2 (a+b x)^3}-\frac {1}{2 b^2 (a+b x)^2}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 20, normalized size = 0.67 \begin {gather*} -\frac {a+3 b x}{6 b^2 (a+b x)^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x/(a + b*x)^4,x]

[Out]

-1/6*(a + 3*b*x)/(b^2*(a + b*x)^3)

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x}{(a+b x)^4} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[x/(a + b*x)^4,x]

[Out]

IntegrateAlgebraic[x/(a + b*x)^4, x]

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fricas [A]  time = 0.77, size = 43, normalized size = 1.43 \begin {gather*} -\frac {3 \, b x + a}{6 \, {\left (b^{5} x^{3} + 3 \, a b^{4} x^{2} + 3 \, a^{2} b^{3} x + a^{3} b^{2}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(b*x+a)^4,x, algorithm="fricas")

[Out]

-1/6*(3*b*x + a)/(b^5*x^3 + 3*a*b^4*x^2 + 3*a^2*b^3*x + a^3*b^2)

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giac [A]  time = 1.01, size = 18, normalized size = 0.60 \begin {gather*} -\frac {3 \, b x + a}{6 \, {\left (b x + a\right )}^{3} b^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(b*x+a)^4,x, algorithm="giac")

[Out]

-1/6*(3*b*x + a)/((b*x + a)^3*b^2)

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maple [A]  time = 0.00, size = 27, normalized size = 0.90 \begin {gather*} \frac {a}{3 \left (b x +a \right )^{3} b^{2}}-\frac {1}{2 \left (b x +a \right )^{2} b^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/(b*x+a)^4,x)

[Out]

1/3*a/b^2/(b*x+a)^3-1/2/b^2/(b*x+a)^2

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maxima [A]  time = 1.37, size = 43, normalized size = 1.43 \begin {gather*} -\frac {3 \, b x + a}{6 \, {\left (b^{5} x^{3} + 3 \, a b^{4} x^{2} + 3 \, a^{2} b^{3} x + a^{3} b^{2}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(b*x+a)^4,x, algorithm="maxima")

[Out]

-1/6*(3*b*x + a)/(b^5*x^3 + 3*a*b^4*x^2 + 3*a^2*b^3*x + a^3*b^2)

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mupad [B]  time = 0.07, size = 44, normalized size = 1.47 \begin {gather*} -\frac {\frac {a}{6\,b^2}+\frac {x}{2\,b}}{a^3+3\,a^2\,b\,x+3\,a\,b^2\,x^2+b^3\,x^3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/(a + b*x)^4,x)

[Out]

-(a/(6*b^2) + x/(2*b))/(a^3 + b^3*x^3 + 3*a*b^2*x^2 + 3*a^2*b*x)

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sympy [A]  time = 0.32, size = 44, normalized size = 1.47 \begin {gather*} \frac {- a - 3 b x}{6 a^{3} b^{2} + 18 a^{2} b^{3} x + 18 a b^{4} x^{2} + 6 b^{5} x^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(b*x+a)**4,x)

[Out]

(-a - 3*b*x)/(6*a**3*b**2 + 18*a**2*b**3*x + 18*a*b**4*x**2 + 6*b**5*x**3)

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